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If y = arctan (cosx - sinx/cosx + sinx), what is dy/dx? - Quora
We have [math]y=\arctan\left ( \frac{\cos x - \sin x}{\cos x + \sin x} \right )[/math] ... Ifsinx + cosx = m and tanx + cotx = n, how do I find a relation between m and n? |
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If dy = [(secx - y) / tanx)]dx, then the curve is: a) y = x(sinx) b) y = x(cosx) c) y = x( secx) d) y = x(cosecx). Answer : d) y = x(cosecx). Solution : To find the required curve, we have to find y by integrating the given equation as ... |
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solve cos ² x (dy/dx) + y = tanx answer : y = tanx - 1 + C exp(-tanx) explanation ... . if y = x sinx , find dy/dx from first principles answer: dy/dx = xcosx +sinx ... |