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Tutors Answer Your Questions about Inequalities (FREE) ... (Show Source): ... 2x +2/5 => 1/2x+2 2x-1/2x => 2-2/5 1.5x => 1 3/5 x => 1.6/1.5 x => 1.07 ... . the answer has to be presented as an inequality, please help ... .. Question 978999: The question is solve the inequality for Algebra II 3x-4/x+3<2 what is the solutio... |
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Ad: You enter your algebra equation or inequality - Algebrator solves it ... Tutors Answer Your Questions about Linear-systems (FREE). Get help ... (Show Source) : ... If each is increased by 10, the ratio b/w the new numbers so formed as 5:7. ... . Question 980625: Grade 9 maths 'please help me solve this equation 3x-4=x+2 |
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Practice Midterm 1 Key - Ltcconline.net
Please work out each of the given problems. ... Show your work. Problem 1 Solve the inequality. Write the ... Problem 5 Let f(x) = 3x + 2, g(x) = x + 3, and c(x) = -1. |
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x = 5, y = 3 is a solution of both equations at the same time, so it is the solution of ... Multiply equation (1) by 7 and equation (2) by 2: ... (2) 5x – 6y = –1, (1) 3x + y = 1 ... Work out the answer to each question then click on the button marked ... .. Solve the simultaneous equations below by elimination, simplifying your answers ... |
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Solving Inequalities Resources | WyzAnt Resources - Tutors
5x+6 >/= -7/4x-1 I subtract 5x from both sides -7/4 - 5/1 = 27/4? 6 >/= -27/4x - 1 ... Show your work ... solve for x and write answer in interval notation 3x/x-2 ≤ 0. |
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Practice Exam 1 - Ltcconline.net
Practice Exam 1. Please work out each of the given problems. ... Show your work. ... First subtract 3 from both sides to set the inequality to 0. 2x2 ... (-5,3/4]. Problem 3 Solve. x1/2 - 2x1/4 - 8 = 0. Solution. Use substitution with ... x3 - 3x2 + 2x = 0. |
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Practice Exam 1 - Ltcconline.net
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Practice Exam 2 - Ltcconline.net
Please work out each of the given problems. ... Show your work. Problem 1 Solve the following inequalities and sketch the solution set on a number line. A. 3x - 5 > 2. Solution. 3x - 5 > 2 add 5 to both sides. 3x > 7 divide both sides by 3. x > 7/3. |